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4k^2+8k-117=0
a = 4; b = 8; c = -117;
Δ = b2-4ac
Δ = 82-4·4·(-117)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-44}{2*4}=\frac{-52}{8} =-6+1/2 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+44}{2*4}=\frac{36}{8} =4+1/2 $
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